This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1894 Excerpt: ...frequent questioning and illustration will soon enable the class to explain the terms used. The theory of construction and the uses of the different instruments must also be carefully and frequently explained. The following course amply covers the requirements, and most of the figures will explain themselves. Notes are ...
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This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1894 Excerpt: ...frequent questioning and illustration will soon enable the class to explain the terms used. The theory of construction and the uses of the different instruments must also be carefully and frequently explained. The following course amply covers the requirements, and most of the figures will explain themselves. Notes are only given where specially needed. Attention is again directed to the necessity of drawing the figures large, in a variety of positions, and of forming numerous exercises from them. A few examination cards are given at the end, which should be arranged upon the paper as directed. Longman's 'Practical Geometry for Standard V' will furnish the teacher with a variety of exercises. The following problem is worked out fully as an illustration of the points which should be dealt with in a lesson: --From a given point A, draw a line which shall meet the line EC at an angle equal to the given angle D. 1 Draw two parallel lines on the board with the set-square. Place the 6o set-square as shown in fig. 421, and draw a line ab cutting both the parallel lines. Apply the set-square to the angle at b, and direct the attention of the pupils to the fact that it exactly fits, and therefore the alternate angles must be equal. Draw another line with the 45 set-square, and show that there is the same result. Now draw two converging lines, and show that the alternate angles are no longer equal. (Explain 'alternate.') 2. Through A draw AE parallel to BC. 3. At A make an angle equal to D, and produce the line to meet BC in F. 4. The angle AFC equals the angle EAF, as has been previously shown, and EAF was constructed equal to D, therefore AFC must be equal to D, and AF is the required line. This is a difficult problem for children, and should be reasoned out as show...
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