The Universal Solution for Numerical and Literal Equations; By Which the Roots of Equations of All Degrees Can Be Expressed in Terms of Their Coefficients
This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1900 Excerpt: ...rule, nor does it require the removal of the second term. It will be further illustrated under the head of general solutions. y = 2.375-V.640625. We now write the quadratics (e) a?-3.5 x + 2.375 +V.640625 = 0. (0 3?-3.5 x + 2.375-VM)625 = 0. Their product equals equation (I). It will be discovered in the solution of ...
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This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1900 Excerpt: ...rule, nor does it require the removal of the second term. It will be further illustrated under the head of general solutions. y = 2.375-V.640625. We now write the quadratics (e) a?-3.5 x + 2.375 +V.640625 = 0. (0 3?-3.5 x + 2.375-VM)625 = 0. Their product equals equation (I). It will be discovered in the solution of the quadratic (e) that the equation contains two real roots and a pair of real imaginaries. Almost an entire solution of the equation is required by the Sturm Theorem in determining the character of the roots. In the general solution no attention is given to the character of roots, for their true character and signs are developed by the solution. Prom (p): It will be shown in the solution of equations of the Sixth Degree that they depend upon the solution of a cubic. From (9), (2)"-2(-13) = 30 = a2 + 62 + c2 + cP + e2 +/- (Th. II.) 184 = the product of the prime factors 2, 2, 2, and 23. The equation is of odd degree, therefore one real root at least. (110.) We now try--2, and find that it satisfies the condition of the equation, and is therefore a root. (16.) We now separate the equation, if possible, into a cubic and biquadratic, letting 2x2x2 = 8 = absolute term of th- cubic. If--2 is one of the roots of the cubic, then will 2x2=4 be the product of the other two roots. We easily form the cubic (A) which has--2 for a root. Dividing (I) by (A) we obtain the biquadratic (B) a;4-2 ar1-13 a;2 +14 a; + 23 = 0. The roots of (B) are easily found, as in the solution of (I). The roots of (B) are all real, two + and two--..-. (q) contains five real roots and a pair of imaginaries. From equation (r), (+ 2)2--2 (--2) = 8 = sum of squares of roots (Th. II.). The equation is of odd degree; therefore, one real + root at least. (110.) The coeffi...
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Add this copy of The Universal Solution for Numerical and Literal to cart. $21.46, new condition, Sold by Ingram Customer Returns Center rated 5.0 out of 5 stars, ships from NV, USA, published 2006 by University of Michigan Library.
Add this copy of The Universal Solution for Numerical and Literal to cart. $36.34, new condition, Sold by Ria Christie Books rated 4.0 out of 5 stars, ships from Uxbridge, MIDDLESEX, UNITED KINGDOM, published 2006 by University of Michigan Library.
Add this copy of The Universal Solution for Numerical and Literal to cart. $39.50, new condition, Sold by Ingram Customer Returns Center rated 5.0 out of 5 stars, ships from NV, USA, published 1900 by University of Michigan Library.
All Editions of The Universal Solution for Numerical and Literal Equations; By Which the Roots of Equations of All Degrees Can Be Expressed in Terms of Their Coefficients
